(1/4x+12)-(1/x^2-9)=(5/x-3)

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Solution for (1/4x+12)-(1/x^2-9)=(5/x-3) equation: 



(1/4x+12)-(1/x^2-9)=(5/x-3)

We move all terms to the left:

(1/4x+12)-(1/x^2-9)-((5/x-3))=0



Domain of the equation: 4x+12)!=0

x∈R





Domain of the equation: x^2-9)!=0

x∈R





Domain of the equation: x-3))!=0

x∈R



We get rid of parentheses

1/4x-1/x^2-((5/x-3))+12+9=0

We calculate fractions

We do not support expression: x^4

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